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3a^2+2a-456=0
a = 3; b = 2; c = -456;
Δ = b2-4ac
Δ = 22-4·3·(-456)
Δ = 5476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5476}=74$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-74}{2*3}=\frac{-76}{6} =-12+2/3 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+74}{2*3}=\frac{72}{6} =12 $
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